Survey Measuments
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- Posts: 8
- Joined: Thu Jan 26, 2006 5:49 pm
- Location: California
Survey Measuments
This may be beyond a support question but any ideas would be appreciated. I'm trying to replicate a land survey diagram that shows land lines as compass measurements in degrees and feet. For example,
N 34.6169 E (107.18 ft)
S 80.267 E (207.84 ft)
N 45.0125 E (91.88 ft)
N 43.75 E (96.03)
N 20.094 E (81.44 ft)
N 45.1139 E (89.53 ft)
I've tried numerous ways to use HighDesign angle functions to lay down the lines but the results have been very confusing. Likely it's my ignorance of surveying concepts or not understanding how HD reports angles. I'm about to give up. That would be a shame since HD should be just to tool to use.
N 34.6169 E (107.18 ft)
S 80.267 E (207.84 ft)
N 45.0125 E (91.88 ft)
N 43.75 E (96.03)
N 20.094 E (81.44 ft)
N 45.1139 E (89.53 ft)
I've tried numerous ways to use HighDesign angle functions to lay down the lines but the results have been very confusing. Likely it's my ignorance of surveying concepts or not understanding how HD reports angles. I'm about to give up. That would be a shame since HD should be just to tool to use.
Did you check the "Bearings" option in the preferences?
Try this:
This makes a line directed to N 34.61.69 E and 107.18ft long.
Try this:
- 1. Go to HighDesign > Preferences.
2. Click the Units panel.
3. In the Linear Units group, set the drawing units to Decimal Feet.
4. In the "Angles" group, set Angles to decimal (0.0000°), Precision to "4 (.0001), click the Bearings button and set the direction of the North. In most topographic maps it is 90 degrees.
This makes a line directed to N 34.61.69 E and 107.18ft long.
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- Posts: 8
- Joined: Thu Jan 26, 2006 5:49 pm
- Location: California
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- Posts: 8
- Joined: Thu Jan 26, 2006 5:49 pm
- Location: California
You said:
"enter the first angle, i.e. "N 34.6169 E" and press Return, push "L", enter the distance (107.18') and press Return. This makes a line directed to N 34.61.69 E and 107.18ft long."
I had coverted my bearing from degrees, min, sec to decimal to get the 34.6169 value. The original bearing is 34 degrees, 36 min, 59 sec. Your comment above states a bearing "N 34.61.69 E". I'm confused.
When I enter N 34.61.69 E the A function at the botton right corner of the HD window shows N 34 37' 1" E. When I enter N 34.6169 E the A shows N30 54' 42" E. Does this happen to you also? Is it an issue of precision? I'd like to see the value of what I enterted verified on the window.
Thanks
"enter the first angle, i.e. "N 34.6169 E" and press Return, push "L", enter the distance (107.18') and press Return. This makes a line directed to N 34.61.69 E and 107.18ft long."
I had coverted my bearing from degrees, min, sec to decimal to get the 34.6169 value. The original bearing is 34 degrees, 36 min, 59 sec. Your comment above states a bearing "N 34.61.69 E". I'm confused.
When I enter N 34.61.69 E the A function at the botton right corner of the HD window shows N 34 37' 1" E. When I enter N 34.6169 E the A shows N30 54' 42" E. Does this happen to you also? Is it an issue of precision? I'd like to see the value of what I enterted verified on the window.
Thanks
Sorry, that was a typo: The last line should be "34.6169", not "34.61.69".hkhamilton wrote:I had coverted my bearing from degrees, min, sec to decimal to get the 34.6169 value. The original bearing is 34 degrees, 36 min, 59 sec. Your comment above states a bearing "N 34.61.69 E". I'm confused.
You can choose to enter angles as deg, min, sec or as decimal values. Simply go to the Preferences and select the one you need.When I enter N 34.61.69 E the A function at the botton right corner of the HD window shows N 34 37' 1" E. When I enter N 34.6169 E the A shows N30 54' 42" E. Does this happen to you also? Is it an issue of precision? I'd like to see the value of what I enterted verified on the window.
"N 34.6169 E" gets converted to "N 30° 54' 42'' E" because you are attempting to enter a decimal value when the app is really expecting degrees, minutes and seconds, so it interprets it as "34.6169 degrees, 0 mins, 0 sec", which is different from 30° 54' 42''.
Hope that's clear enough. Angle conversions and bearings are not the funniest things in the world.
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- Posts: 8
- Joined: Thu Jan 26, 2006 5:49 pm
- Location: California
curved site lines...
Hi guys,
Just neede to use this post... great.
One other thing though, which I am pretty desperate to know; what about when some of the lines are curved? Like: R=330', A=11°37'30", L=66.96.
Thanks.
macitect
Just neede to use this post... great.
One other thing though, which I am pretty desperate to know; what about when some of the lines are curved? Like: R=330', A=11°37'30", L=66.96.
Thanks.
macitect
Thanks for the help Alex, but I am still a little puzzled... and perhaps I should wait until I get home but, which command do I use? I was clicking on circle and then using the curved line by three points method. Is that the correct way or how would I draw curved lines with this info?
thanks again,
derek
thanks again,
derek
I believe I did it using center point method, where L would indicate the radius, A indicates the angle from start to end. Then you'll have to drag the completed arc into the correct location using its endpoints.... maybe three point arc will follow the same routine.
I'll have to try it when I get home too... double life of one job on windows machines and the other on the mac. Too bad there's not a mac emulator to run tiger
I'll have to try it when I get home too... double life of one job on windows machines and the other on the mac. Too bad there's not a mac emulator to run tiger
fat guy in a little coat
Hi ybalx,
so your method worked for me, the only problem I still can't figure out is controlling which part of the circle my line actually begins. If I want an angle of around 11}{~´¯µ[/b]
so your method worked for me, the only problem I still can't figure out is controlling which part of the circle my line actually begins. If I want an angle of around 11}{~´¯µ
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